write a program to show user defined Exception in the following condition: you have to enter the salary of a person at runtime and the salary must be a non-negative number & should be in between 6,000 & 20,000. and if it is not it will throw a user defined exception named.

class MyException extends Exception

{

 private int salary;

 MyException(int s)

  {

  salary=s;

  }

 public String toString()

  {

    return "MyException[" + salary +"]";

  }

 }

class ExceptionDemo

 {

  static void compute(int s) throws MyException

  {

   System.out.println("main exception(" + s + ")");

   if((s>60000)&&(s<20000))

   throw new MyException(s);

   System.out.println("no exception");

  }

 public static void main(String args[])

  {

  try

   {

   int s=Integer.parseInt(System.console().readLine("Enter the salary :"));

   compute(s);

   }

   catch(MyException e)

   {

      System.out.println("caugth;"+e);

   }

  }

 }